1 232 34543 4567654 567898765
int main()
{
int i,j,k;
for(i=1;i<=5;i++)
{
j=i;
for(k=1;k<=i;k++)
{
printf("%d",j++);
}
j-=2;
for(k=j;k>=i;k--)
{
printf("%d",j--);
}
printf("\n");
}
return 0;
}
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java pattern can u help me
ReplyDeletehow to achieve this pattern
ReplyDelete1
2 3 2
3 4 5 4 3
4 5 6 7 6 5 4
5 6 7 8 9 8 7 6 5
6 7 8 9 0 1 0 9 8 7 6
7 8 9 0 1 2 3 2 1 0 9 8 7
i can't understand can you please teach me by a video
DeleteIn the above code consider j-=1,then it's correct
ReplyDelete1 1 1 1 1
ReplyDelete1 2 2 2 1
1 2 3 2 1
1 2 2 2 1
1 1 1 1 1
can any one solve this
543212345
ReplyDelete4321234
32123
212
11
#include
Deleteint main()
{
int i, j, n, k ,s=0;
printf("no:");
scanf_s("%d", &n);
for (k = n; k >= 1; k--)
{
for (j = 1; j <= s; j++)
{
printf(" ");
}
for (i = k; i >= 1; i--)
{
printf("%d", i);
}
for (i = 2; i < k; i++)
{
printf("%d", i);
}
printf("%d",k);
printf("\n");
s++;
}
return 0;
}
anyone plz
ReplyDelete