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Number Patterns 


12345
1234
123
12
1
 
12345
2345
345
45
5
Code of above pattern


 Code of above pattern


 
54321
4321
321
21
1
 
54321
5432
543
54
5
Code of above pattern


 Code of above pattern


 
1
12
123
1234
12345
 
5
45
345
2345
12345
Code of above pattern


 Code of above pattern


 
1
21
321
4321
54321

5
54
543
5432
54321
Code of above pattern


 Code of above pattern


1
22
333
4444
55555

5
44
333
2222
11111
Code of above pattern


 Code of above pattern


 
55555
4444
333
22
1

11111
2222
333
44
5
Code of above pattern


 Code of above pattern


 
12345
4321
123
21
1

1234567
12345
123
1
Code of above pattern


 Code of above pattern


 
1
01
101
0101

13579
3579
579
79
9
Code of above pattern


 Code of above pattern


 
1
2 4
1 3 5
2 4 6 8
1 3 5 7 9

55555
45555
34555
23455
12345
Code of above pattern


 Code of above pattern


 
1
23
456
78910

1
10
101
1010
10101
Code of above pattern


 Code of above pattern


 
1 
2 6 
3 7 10 
4 8 11 13 
5 9 12 14 15

1
123
12345
1234567
Code of above pattern


 Code of above pattern


 
12344321
123**321
12****21
1******1

    1
  2 3 4
5 6 7 8 9
Code of above pattern


 Code of above pattern


 
1   2   3   4   5   6   7   8   9   10
36  37  38  39  40  41  42  43  44  11
35  64  65  66  67  68  69  70  45  12
34  63  84  85  86  87  88  71  46  13
33  62  83  96  97  98  89  72  47  14
32  61  82  95  100 99  90  73  48  15
31  60  81  94  93  92  91  74  49  16
30  59  80  79  78  77  76  75  50  17
29  58  57  56  55  54  53  52  51  18
28  27  26  25  24  23  22  21  20  19
Code of above pattern


 
11111
2222
333
22
1

5432*
543*1
54*21
5*321
*4321
Code of above pattern


 Code of above pattern


 
1
121
12321
1234321

0 
909 
89098 
7890987 
678909876 
56789098765 
4567890987654 
345678909876543 
23456789098765432 
1234567890987654321
Code of above pattern


 Code of above pattern


 
1        1
12      21
123    321
1234  4321
1234554321

    1
   21
  321
 4321
54321
Code of above pattern


 Code of above pattern


 
1
232
45654
78910987

1
2*2
3*3*3
4*4*4*4
4*4*4*4
3*3*3
2*2
1
Code of above pattern


 Code of above pattern


 
11
12 13
13 14 15
14 15 16 17

             1
           2 3
         4 5 6
      7 8 9 10
11 12 13 14 15
Code of above pattern


 Code of above pattern


 
    5
   54
  543
 5432
54321

1
212
32123
4321234
Code of above pattern


 Code of above pattern


 
1
23
345
4567
56789

  1  2  3  4  5
  6  7  8  9
 10 11 12
 13 14
 15
Code of above pattern


 Code of above pattern


 
1234
2341
3421
4321

11111
0000
111
00
1
Code of above pattern


 Code of above pattern


 
                  1  
              4   9  16 
         25  36  49  64  81 
    100 121 144 169 196 225 256 
289 324 361 400 441 484 529 576 625

11111
1   1
1   1
1   1
11111
Code of above pattern


 Code of above pattern


 
    1 
   1 2 
  1 2 3 
 1 2 3 4 
1 2 3 4 5

    1
   123
  12345
 1234567
123456789
 1234567
  12345
   123
    1
Code of above pattern


 Code of above pattern


 
*000*000*
0*00*00*0
00*0*0*00
000***000

5 5 5 5 5 5 5 5 5 
5 4 4 4 4 4 4 4 5 
5 4 3 3 3 3 3 4 5 
5 4 3 2 2 2 3 4 5 
5 4 3 2 1 2 3 4 5 
5 4 3 2 2 2 3 4 5 
5 4 3 3 3 3 3 4 5 
5 4 4 4 4 4 4 4 5 
5 5 5 5 5 5 5 5 5
Code of above pattern


 Code of above pattern


 
1
1 1
1 2 1
1 3 3 1 
1 4 6 4 1

1
2 4
3 6 9
4 8 12 16
5 10 15 20 25
6 12 18 24 30 36
7 14 21 28 35 42 49
8 16 24 32 40 48 56 64
9 18 27 36 45 54 63 72 81
10 20 30 40 50 60 70 80 90 100
Code of above pattern


 Code of above pattern


 
1 
1 2 
3 5 8 
13 21 34 55 
89 144 233 377 610

11111
10001
10001
10001
11111
Code of above pattern


 Code of above pattern


 
1 2 3 4 5 
2 1 2 3 4 
3 2 1 2 3 
4 3 2 1 2 
5 4 3 2 1 

1
3 2
4 5 6
10 9 8 7
11 12 13 14 15
Code of above pattern


 Code of above pattern


 
1
232
34543
4567654
567898765 

1     1
 2   2 
  3 3  
   4   
  3 3  
 2   2 
1     1
Code of above pattern


 Code of above pattern

 
1     
2 6    
3 7 10   
4 8 11 13  
5 9 12 14 15  

        1       
      1 2 1     
    1 2 3 2 1   
  1 2 3 4 3 2 1 
1 2 3 4 5 4 3 2 1
Code of above pattern


 Code of above pattern

 
      1
    2   2
  3       3
4           4
  3       3
    2   2
      1

1  2  3  4  5  
16          6  
15          7  
14          8  
13 12 11 10 9
Code of above pattern


 Code of above pattern


 
N=39714

3 9 1 7 4
9 1 7 4
1 7 4
7 4
4
Code of above pattern


Related Links:
Star Patterns
http://cbasicprogram.blogspot.in/2012/03/star-patterns.html

Alphabet Patterns
http://cbasicprogram.blogspot.in/2013/03/alphabet-patterns.html

Series Programs
http://cbasicprogram.blogspot.in/2013/01/series-program.html
Labels: ,

1,014 comments:

  1. AnonymousOctober 8, 2012 at 12:38 AM

    thanks for this one...

    ReplyDelete
  2. AnonymousJanuary 21, 2013 at 7:22 PM

    please bro i need code for this pattern..

    1
    123
    12345
    1234567
    12345
    123
    1

    ReplyDelete
    Replies
    1. Nimish GargJanuary 21, 2013 at 8:01 PM

      for(i=1;i<=7;i+=2)
      {
      for(j=1;j<=i;j++)
      printf("%d",j);
      printf("\n");
      }
      for(i=5;i>=1;i-=2)
      {
      for(j=1;j<=i;j++)
      printf("%d",j);
      printf("\n");
      }

      Delete
    2. UnknownAugust 30, 2018 at 11:49 AM

      1 5
      2 4
      3

      Delete
  3. AnonymousJanuary 25, 2013 at 1:30 PM

    1 5 8 10
    2 6 9
    3 7
    4
    reply plzzzz!!

    ReplyDelete
    Replies
    1. Nimish GargJanuary 25, 2013 at 3:28 PM

      for(i=1;i<=4;i++)
      {
      printf("%d",k=i;);
      for(j=4;j>i;j--)
      printf("%d",k+=j);
      printf("\n");
      }

      Delete
    2. UnknownOctober 22, 2015 at 4:03 PM

      Good logic bro

      Delete
    3. UnknownSeptember 20, 2018 at 11:42 PM

      7 8 9 10
      4 5 6
      2 3
      1
      Please send the logic for this pattern

      Delete
  4. AnonymousJanuary 25, 2013 at 8:23 PM

    ohhh!!! thanx a lot...

    ReplyDelete
  5. දිලීපFebruary 7, 2013 at 9:25 AM

    can any one tell how to print this patterns ?
    Q1:
    11111
    22222
    33333
    44444
    55555

    Q2:
    12345
    12345
    12345
    12345

    ReplyDelete
    Replies
    1. Nimish GargFebruary 7, 2013 at 11:23 AM

      11111
      22222
      33333
      44444
      55555
      for(i=1;i<=5;i++)
      {
      for(j=1;j<=5;j++)
      printf("%d",i);
      printf("\n");
      }

      12345
      12345
      12345
      12345
      for(i=1;i<=5;i++)
      {
      for(j=1;j<=5;j++)
      printf("%d",j);
      printf("\n");
      }

      Delete
  6. AnonymousFebruary 10, 2013 at 11:27 AM

    what is logic of pattent

    1234321
    123 321
    12 21
    1 1

    ReplyDelete
    Replies
    1. Nimish GargFebruary 28, 2013 at 8:59 PM

      void main()
      {
      int i,j,k;
      for(i=4;i>=1;i--)
      {
      for(j=1;j<=4;j++)
      {
      if(j<=i)
      printf("%d",j);
      else
      printf(" ");
      }
      for(j=3;j>=1;j--)
      {
      if(j<=i)
      printf("%d",j);
      else
      printf(" ");
      }
      printf("\n");
      }
      }

      Delete
    2. AnonymousJanuary 30, 2016 at 11:36 PM

      a million thanks

      Delete
    3. UnknownAugust 20, 2018 at 5:44 PM

      This comment has been removed by the author.

      Delete
  7. AnonymousFebruary 18, 2013 at 6:37 PM

    please help me out with this
    z y x w v w x y z
    z y x w x y z
    z y x y z
    z y z
    z

    ReplyDelete
    Replies
    1. Nimish GargFebruary 18, 2013 at 7:23 PM

      void main()
      {
      int i,j;
      clrscr();
      for(i=5;i>=1;i--)
      {
      for(j=1;j<=i;j++)
      printf("%c ",123-j);
      for(j-=2;j>=1;j--)
      printf("%c ",123-j);
      printf("\n");
      }
      getch();
      }

      Delete
  8. KrunalFebruary 25, 2013 at 5:54 PM

    How to print this pyramid

    1 2 3 4 5
    .4 3 2 1
    ..1 2 3
    ....2 1
    .....1

    ReplyDelete
    Replies
    1. Nimish GargFebruary 25, 2013 at 6:01 PM

      this should work, not tested ...
      for(i=5;i>=1;i--)
      {
      for(j=5;j>i;j--)
      {
      printf(" ");
      }
      for(k=1;k<=i;k++)
      {
      printf("%d ",k);
      }
      printf("\n");
      }

      Delete
    2. AnonymousJuly 3, 2013 at 11:27 PM

      it workd..i wantd fr * patrn.. thanx !

      Delete
    3. AnonymousFebruary 5, 2016 at 4:52 PM

      It works.. thank you

      Delete
    4. UnknownSeptember 9, 2018 at 7:04 PM

      it works but upto
      1 2 3 4 5 6
      1 2 3 4 5
      1 2 3 4
      1 2 3
      1 2
      1

      Delete
  9. UnknownFebruary 28, 2013 at 8:16 PM

    How to print this
    ABCDEFEDCBA
    ABCDE.EDCBA
    ABCD…..DCBA
    ABC……….CBA
    AB……………BA
    A……………...A
    plzz help!! Dots are spaces …

    ReplyDelete
    Replies
    1. Nimish GargFebruary 28, 2013 at 8:57 PM

      void main()
      {
      int i,j,k;
      for(i=5;i>=1;i--)
      {
      for(j=1;j<=5;j++)
      {
      if(j<=i)
      printf("%c",'A' + j-1);
      else
      printf(" ");
      }
      for(j=4;j>=1;j--)
      {
      if(j<=i)
      printf("%c",'A' + j-1);
      else
      printf(" ");
      }
      printf("\n");
      }
      }

      Delete
    2. Pranav JainJuly 3, 2015 at 12:18 AM

      superb man!!!!!!!!!!!!!!!!

      Delete
    3. UnknownOctober 22, 2015 at 4:53 PM

      Awesome thinking man!!!!!!!!

      Delete
  10. NEEV BLOGFebruary 28, 2013 at 11:31 PM

    1
    1
    2
    12
    3
    123
    4
    1234 plz help

    ReplyDelete
    Replies
    1. Nimish GargMarch 1, 2013 at 11:21 AM

      int main()
      {
      int i, j;
      for(i=1;i<=4;i++)
      {
      printf("%d\n",i);
      for(j=1;j<=i;j++)
      {
      printf("%d",j);
      }
      printf("\n");
      }
      }

      Delete
  11. UnknownMarch 7, 2013 at 9:41 PM

    A
    11
    BBB
    22222
    CCCCC

    ReplyDelete
    Replies
    1. Nimish GargMarch 8, 2013 at 11:26 AM

      void main()
      {
      int i, j;
      for(i=1;i<=5;i++)
      {
      for(j=1;j<=i;j++)
      {
      if(i%2==0)
      printf("%d",i/2);
      else
      printf("%c",'A' + i/2);
      }
      printf("\n");
      }
      }

      Delete
    2. Rare Graphic DesignsJanuary 11, 2016 at 10:49 PM

      Nimish your program works properly..

      Delete
  12. AnonymousMarch 13, 2013 at 9:30 AM

    Pls help me.....

    54321
    _5432
    __543
    ___54
    ____5


    ____5
    ___45
    __345
    _2345
    12345

    _is space....

    ReplyDelete
    Replies
    1. Nimish GargMarch 13, 2013 at 9:31 AM

      54321
      _5432
      __543
      ___54
      ____5

      main()
      {
      int i,j;
      for(i=5;i>=1;i--)
      {
      for(j=5;j>=1;j--)
      {
      if(j>i)
      printf(" ");
      else
      printf("%d",j);
      }
      printf("\n");
      }
      }

      Delete
    2. Nimish GargMarch 13, 2013 at 9:34 AM

      ____5
      ___45
      __345
      _2345
      12345

      main()
      {
      int i,j;
      for(i=5;i>=1;i--)
      {
      for(j=1;j<=5;j++)
      {
      if(j<i)
      printf(" ");
      else
      printf("%d",j);
      }
      printf("\n");
      }
      }

      Delete
  13. AnonymousMarch 13, 2013 at 9:39 AM

    54321
    *4321
    **321
    ***21
    ****1

    12345
    *2345
    **345
    ***45
    ****5

    ****5
    ***45
    **345
    *2345
    12345

    Pls help me with these programs pls...i need space where * is written.

    Thank you

    ReplyDelete
    Replies
    1. Nimish GargMarch 13, 2013 at 9:41 AM

      54321
      *4321
      **321
      ***21
      ****1

      main()
      {
      int i,j;
      for(i=5;i>=1;i--)
      {
      for(j=5;j>=1;j--)
      {
      if(i<j)
      printf(" ");
      else
      printf("%d",j);
      }
      printf("\n");
      }
      }

      Delete
    2. Nimish GargMarch 13, 2013 at 9:43 AM

      12345
      *2345
      **345
      ***45
      ****5

      main()
      {
      int i,j;
      for(i=1;i<=5;i++)
      {
      for(j=1;j<=5;j++)
      {
      if(j<i)
      printf(" ");
      else
      printf("%d",j);
      }
      printf("\n");
      }
      }

      Delete
    3. Nimish GargMarch 13, 2013 at 9:44 AM

      ****5
      ***45
      **345
      *2345
      12345

      main()
      {
      int i,j;
      for(i=5;i>=1;i--)
      {
      for(j=1;j<=5;j++)
      {
      if(j<i)
      printf(" ");
      else
      printf("%d",j);
      }
      printf("\n");
      }
      }

      Delete
  14. Shashwat DixitMarch 14, 2013 at 3:39 PM

    i want to print

    c
    co
    com
    comp
    compu
    comput
    compute
    computer

    please tell me the programme to write the above
    thankssssssss

    ReplyDelete
    Replies
    1. Nimish GargMarch 14, 2013 at 4:37 PM

      #include
      #include
      int main()
      {
      char s[]="computer";
      int i,j;
      for(i=0;s[i];i++)
      {
      for(j=0;j<=i;j++)
      printf("%c",s[j]);
      printf("\n");
      }
      return 0;
      }

      Delete
    2. kalpanaSeptember 24, 2014 at 9:53 PM

      sir plzz tellme this program using manipulators in c++

      Delete
  15. Shashwat DixitMarch 14, 2013 at 3:41 PM

    sir can you give me your phone no. or email ID so that i can contact you directly....

    ReplyDelete
  16. AnonymousMarch 15, 2013 at 10:40 PM

    What is the code for ??
    1 2 3 4 4 3 2 1
    1 2 3 3 2 1
    1 2 2 1
    1 1

    ReplyDelete
    Replies
    1. Nimish GargMarch 15, 2013 at 11:05 PM

      void main()
      {
      int i,j,k;
      for(i=4;i>=1;i--)
      {
      for(j=1;j<=i;j++)
      {
      printf("%d",j);
      }
      for(j=i;j>=1;j--)
      {
      printf("%d",j);
      }
      printf("\n");
      }
      }

      Delete
  17. NitinMarch 23, 2013 at 1:33 AM

    1
    232
    23432
    help me for this

    ReplyDelete
    Replies
    1. Nimish GargMarch 25, 2013 at 1:45 PM

      printf("1\n");
      for(i=3;i<=4;i++)
      {
      for(j=2;j<=i;j++)
      printf("%d",j);
      for(j=i-1;j>=2;j--)
      printf("%d",j);
      printf("\n");
      }

      Delete
  18. UnknownMarch 23, 2013 at 9:22 AM

    what is program for this?
    *##
    #*#
    ##*
    help!

    ReplyDelete
    Replies
    1. Nimish GargMarch 25, 2013 at 12:57 PM

      for(i=1;i<=3;i++)
      {
      for(j=1;j<=3;j++)
      {
      if(i==j) printf("*");
      else printf("#");
      }
      printf("\n");
      }

      Delete
  19. UnknownApril 1, 2013 at 3:20 PM

    how this can be code in c
    1*3*5*7
    2*4*6
    3*11
    8*10
    13
    pls help as soon as possible

    ReplyDelete
  20. UnknownApril 15, 2013 at 5:04 PM

    *
    *A*
    *A*A*
    *A*A*A*

    help plz.

    ReplyDelete
    Replies
    1. Nimish GargApril 15, 2013 at 7:17 PM

      for(i=1;i<=5;i++)
      {
      for(j=1;j<=i;j++)
      {
      if(j%2==0) printf("A");
      else printf("*");
      }
      printf("\n");
      }

      Delete
  21. AnonymousMay 4, 2013 at 12:31 PM

    Please give the solutionof modular program to read n numbers and find divisors of each of them........

    ReplyDelete
  22. UnknownJuly 3, 2013 at 12:06 AM

    what is the programe
    1
    23
    456
    7890
    12345

    ReplyDelete
    Replies
    1. Nimish GargJuly 3, 2013 at 12:17 PM

      int main()
      {
      int i,j,k;
      k=1;
      for(i=1;i<=5;i++)
      {
      for(j=1;j<=i;j++)
      {
      if(k==10) k=0;
      printf("%d",k++);
      }
      printf("\n");
      }
      }

      Delete
  23. UnknownJuly 18, 2013 at 10:32 PM

    1
    12
    121
    1212

    ReplyDelete
    Replies
    1. Nimish GargSeptember 24, 2013 at 6:24 PM

      tweak with http://cbasicprogram.blogspot.in/2012/04/number-pattern-20.html

      in inner loop replace
      printf("%d",j%2);

      with

      if (j%2==0)
      printf("2");
      else
      printf("1");

      Delete
  24. Wifi DhabaAugust 2, 2013 at 9:25 PM

    1 2 3 4 5
    16 6
    15 7
    14 8
    13 12 11 10 9

    ReplyDelete
    Replies
    1. Nimish GargAugust 5, 2013 at 8:44 AM

      Tweak with this http://cbasicprogram.blogspot.in/2012/05/perfect-square.html

      Delete
  25. UnknownAugust 9, 2013 at 3:12 PM

    1
    1 4
    1 4 9
    1 4 9 16
    1 4 9 16 25

    ReplyDelete
    Replies
    1. Nimish GargAugust 9, 2013 at 4:08 PM

      http://cbasicprogram.blogspot.in/2012/04/number-pattern-1.html
      in above program just change printf("%d",j); to printf("%d",j*j);

      Delete
  26. UnknownSeptember 10, 2013 at 6:23 PM

    how will we print this
    1234
    14 5
    13 6
    12 7
    111098

    ReplyDelete
    Replies
    1. Nimish GargSeptember 10, 2013 at 7:37 PM

      tweak with http://cbasicprogram.blogspot.in/2012/05/perfect-square.html

      Delete
  27. AnonymousSeptember 11, 2013 at 11:32 AM

    1 2 3
    4 5
    6 7 8 9
    10 11 12
    13 14
    15

    Help please!
    TIA!

    ReplyDelete
  28. UnknownSeptember 13, 2013 at 11:17 AM

    will you please help me this
    1
    232
    23432
    2345432

    ReplyDelete
    Replies
    1. Nimish GargSeptember 20, 2013 at 7:42 PM

      tweak with http://cbasicprogram.blogspot.in/2012/04/number-pattern-27.html

      Delete
  29. Siddharth MOctober 6, 2013 at 9:53 PM

    Thank you very much... :)
    u helped me a lot..

    ReplyDelete
  30. AnonymousOctober 13, 2013 at 8:05 AM

    55555
    55555
    45555
    34555
    23455
    12345

    how to make it? plzzzz teach me..... what im going to do is a rectangular, so there will be extra one lane compare to it's base...

    ReplyDelete
    Replies
    1. Nimish GargOctober 15, 2013 at 8:33 AM

      http://cbasicprogram.blogspot.in/2012/04/number-pattern-18.html
      Print extra line before the loop, or start loop with 6 and if i=6 then print i else rest of the logic

      Delete
  31. AnonymousOctober 15, 2013 at 7:30 AM

    5 5 5 5 5
    5 5
    5 5
    5 5
    5 5 5 5 5
    code for this plz.............

    ReplyDelete
    Replies
    1. Nimish GargOctober 15, 2013 at 8:24 AM

      use http://cbasicprogram.blogspot.in/2013/01/number-pattern-42.html
      and print 5 instead of 1

      Delete
  32. AnonymousOctober 16, 2013 at 1:26 PM

    1
    3 5
    7 9 11
    13 15 17 19
    21 23 25 27 29

    ReplyDelete
    Replies
    1. Nimish GargOctober 16, 2013 at 2:48 PM

      http://cbasicprogram.blogspot.in/2012/04/number-pattern-19.html
      just modify it to increment k by 2 instead of 1

      Delete
  33. AnonymousOctober 28, 2013 at 9:23 PM

    1
    13
    135
    1357

    ReplyDelete
    Replies
    1. Nimish GargNovember 18, 2013 at 1:02 PM

      http://cbasicprogram.blogspot.in/2012/04/number-pattern-1.html
      change from printf("%d",j);
      to printf("%d",(j*2)-1);

      Delete
  34. UnknownNovember 2, 2013 at 12:37 AM

    plz help me in this

    *****1
    ****12
    ***123
    **1234
    *12345
    123456

    ReplyDelete
    Replies
    1. Nimish GargNovember 18, 2013 at 12:57 PM

      Just add following loop as first inner loop
      http://cbasicprogram.blogspot.in/2012/04/number-pattern-1.html
      for(j=4;j>=i;j--)
      {
      printf("*");
      }

      Delete
  35. UnknownNovember 17, 2013 at 12:59 PM

    5
    15 5
    25 15 5
    35 25 15 5


    help me plz

    ReplyDelete
    Replies
    1. Nimish GargNovember 18, 2013 at 12:43 PM

      http://cbasicprogram.blogspot.in/2012/04/number-pattern-3.html
      just modify printf("%d",j);
      to printf("%d ",(j*10)-5);

      Delete
  36. UnknownNovember 24, 2013 at 6:40 AM

    Its very helpful for me Thanks :)

    ReplyDelete
  37. UnknownDecember 15, 2013 at 2:40 AM

    @nimish
    dude you are awesome ....so helpful blog !!
    keep updating...tc

    ReplyDelete
  38. UnknownFebruary 15, 2014 at 10:53 PM

    ya its very usefull for us.......

    ReplyDelete
  39. AnishMarch 28, 2014 at 1:43 PM

    please write here the solution :

    1
    2 5
    6 9 14
    15 18 23 30
    31 34 39 46 57

    ReplyDelete
    Replies
    1. Nimish GargMarch 28, 2014 at 6:41 PM

      hit for rows
      1 + 1x1 = 2
      2 + 2x2 = 6
      6 + 3x3 = 15
      15 + 4x4 = 31
      31 + 5x5 = 56

      for columns
      add 3,5,7,9...

      Delete
  40. AnonymousApril 4, 2014 at 8:08 PM

    thanks,this program is very helpful for me.....!!!!!!!

    ReplyDelete
  41. UnknownAugust 22, 2014 at 8:59 PM

    _ _ 1
    _ 2
    3 _ _
    _ 4 _
    _ _ 5

    Sir, Could you Please reply for This Pattern. It would be very helpful sir
    Thank u

    ReplyDelete
    Replies
    1. Nimish GargAugust 22, 2014 at 9:30 PM

      for(i=1;i<=5;i++)
      {
      for(j=1;j<=3-i;j++)
      printf(" ");
      for(j=4;j<=i;j++)
      printf(" ");
      printf("%d\n",i);
      }

      Delete
  42. AnonymousAugust 23, 2014 at 5:42 AM

    please write here the solution :
    1
    3 2
    4 5 6
    10 9 8 7
    11 12 13 14

    ReplyDelete
    Replies
    1. Nimish GargAugust 26, 2014 at 7:40 PM

      http://cbasicprogram.blogspot.in/2013/01/number-pattern-52.html

      Delete
  43. UnknownAugust 27, 2014 at 12:11 AM

    plss i need this to be done.. wap to generate the foll pattern:
    1
    232
    34543
    4567654
    567898765

    ReplyDelete
    Replies
    1. Nimish GargAugust 27, 2014 at 9:20 AM

      http://cbasicprogram.blogspot.in/2013/01/number-pattern-53.html

      Delete
  44. AnonymousSeptember 2, 2014 at 12:09 PM

    plz give the coding of this in c++

    11
    1212
    123123
    12341234

    ReplyDelete
    Replies
    1. Nimish GargSeptember 2, 2014 at 1:17 PM

      simply use inner J loop 2 times of http://cbasicprogram.blogspot.in/2012/04/number-pattern-1.html

      Delete
  45. kin98_bsSeptember 2, 2014 at 7:49 PM

    How to find the sum of following series:-

    (1) + (1+2) + (1+2+3) + (1+2+3+4)....... upto n number of terms

    ReplyDelete
    Replies
    1. Nimish GargSeptember 3, 2014 at 9:59 AM

      http://cbasicprogram.blogspot.in/2013/01/series-program.html

      Delete
  46. kin98_bsSeptember 4, 2014 at 7:34 PM

    How to find the following sum:-

    1/2 - 2/3 + 3/4 -4/5 + 5/6...... upto n number of terms

    ReplyDelete
    Replies
    1. Nimish GargSeptember 5, 2014 at 10:06 AM

      http://cbasicprogram.blogspot.in/2013/01/series-program-9.html

      for Series programs please put your comments on Series Programs Page
      http://cbasicprogram.blogspot.in/2013/01/series-program.html

      Delete
  47. AnonymousSeptember 21, 2014 at 10:58 AM

    it is very useful for me thanks a lot!!!!!

    ReplyDelete
  48. AnonymousSeptember 29, 2014 at 6:31 AM

    _ _ _ _ 1_ _ _ _
    _ _ _ 1 2 1_ _ _
    _ _ 1 2 3 2 1_ _
    _ 1 2 3 4 3 2 1_
    1 2 3 4 5 4 3 2 1

    What would be the code for this pattern?
    (Ignore '_'. Used for indenting)

    ReplyDelete
    Replies
    1. Nimish GargSeptember 29, 2014 at 9:46 AM

      http://cbasicprogram.blogspot.in/2013/01/number-pattern-56.html

      Delete
  49. viraalOctober 5, 2014 at 8:53 PM

    Please give code for:
    ___________1
    ________2_____2
    _____3___________3
    _ 4__________________4
    _____3___________3
    ________2_____2
    ___________1

    ReplyDelete
    Replies
    1. Nimish GargOctober 8, 2014 at 3:44 PM

      http://cbasicprogram.blogspot.in/2013/01/number-pattern-57.html

      Delete
  50. AnonymousOctober 8, 2014 at 10:40 PM

    1 2 3 4 5
    16 6
    15 7
    14 8
    13 12 11 10 9


    Please tell me how to print above pattern?

    ReplyDelete
    Replies
    1. Nimish GargOctober 10, 2014 at 9:49 AM

      http://cbasicprogram.blogspot.com/2013/01/number-pattern-58.html

      Delete
  51. UnknownFebruary 8, 2015 at 5:26 PM

    WAP to get the sum of series 1+2 pow x+3 pow x+.......+n pow x

    ReplyDelete
  52. UnknownMarch 4, 2015 at 7:36 AM

    Sir Plz upload Linked list concepts and Programs

    ReplyDelete
  53. ssvMay 24, 2015 at 2:39 PM

    series of numbers entered by user the program is to check weather the the user entered in series or not

    ReplyDelete
  54. UnknownMay 29, 2015 at 5:35 PM

    Very Helpful for Freshers.....

    ReplyDelete
  55. UnknownJune 4, 2015 at 12:42 PM

    can anyone tell me the code to print the following structure

    1
    3 5
    7 9 11

    ReplyDelete
  56. shubhJune 23, 2015 at 6:40 PM

    1,2,3,6,9,18,27,54 how to print this series

    ReplyDelete
    Replies
    1. Nimish GargJune 23, 2015 at 6:48 PM

      http://cbasicprogram.blogspot.com/2013/01/series-program-10.html

      Delete
  57. UnknownJuly 2, 2015 at 1:37 PM

    thnxxx a lot @nimish sir.....its very helpful for me....keep updating sir..and give me your email id for contact ... thnkuuu so much

    ReplyDelete
  58. AnonymousJuly 2, 2015 at 3:30 PM

    program for:
    1
    1 1
    1 2 1
    1 3 3 1
    1 4 6 4 1

    ReplyDelete
    Replies
    1. Nimish GargJuly 2, 2015 at 3:42 PM

      http://cbasicprogram.blogspot.in/2013/01/pascal-triangle.html

      Delete
  59. AnonymousJuly 2, 2015 at 8:38 PM

    how to display the pattern with a number
    eg:- N=39714

    3 9 1 7 4
    9 1 7 4
    1 7 4
    7 4
    4

    ReplyDelete
  60. UnknownSeptember 9, 2015 at 12:52 PM

    This web blogspot is best among all I have ever seen you are doing good job nimish bro I got cleared many doutsdouts thanks.

    ReplyDelete
  61. UnknownSeptember 29, 2015 at 8:35 PM

    thanks a lot for this logics . its asome blog for beginers of C

    ReplyDelete
  62. Subhadeep DeyOctober 14, 2015 at 11:49 PM

    This is one of the vast collections of pattern programming in C!
    Thanks for your work!

    ReplyDelete
  63. AnonymousOctober 15, 2015 at 9:38 PM

    thanks a lot for logics ....this blog is very helpful

    ReplyDelete
  64. melbourne web developerOctober 30, 2015 at 8:52 AM

    thank you for the information, this is very useful

    ReplyDelete
  65. UnknownNovember 3, 2015 at 10:03 AM

    WAP to calculate the sum of a given no. 123=1 2 3=6.. Help me in solving this program

    ReplyDelete
  66. UnknownApril 17, 2016 at 9:28 PM

    Hey you are doing great job .! kudos to you .
    can I have your Email id so that i can resolve my stuff on mail

    ReplyDelete
  67. UnknownAugust 30, 2016 at 7:18 PM

    Really helpful...thank you so much.....

    ReplyDelete
  68. Divesh DiggiwalSeptember 5, 2016 at 1:57 PM

    nice blog

    ReplyDelete
  69. AnonymousFebruary 3, 2017 at 3:17 PM

    is there is any simple logic for pattern programs

    ReplyDelete
  70. UnknownFebruary 16, 2017 at 11:48 AM

    Hi Sir I Want To Learning Functions OOP In C++ ;

    ReplyDelete
  71. sapsolutionsJune 2, 2017 at 8:03 PM

    Good logics sir

    ReplyDelete
  72. AnonymousJune 10, 2017 at 2:15 PM

    how have you developed good coding skills? can you reply?

    ReplyDelete
  73. AnonymousAugust 4, 2017 at 1:04 PM

    Sir can u tell me how to understand a number pattern program

    ReplyDelete
  74. AnonymousAugust 9, 2018 at 7:03 AM

    Sir thanks for ur solutions can u please write the code for below pattern
    1
    2 9
    3 8 10
    4 7 11 14
    5 6 12 13 15

    ReplyDelete
  75. AnonymousAugust 10, 2018 at 1:55 PM

    hi sir i want coding for this one please help me well the question is printing the matrix in spiral form .
    1 2 3
    4 5 6
    7 8 9
    and the output is 4 5 7 8 9 6 3 2 1

    ReplyDelete
  76. manikantaAugust 11, 2018 at 7:39 PM


    hi sir i want coding for
    1
    12
    123
    1234
    12345

    ReplyDelete
  77. manikantaAugust 11, 2018 at 7:40 PM

    hi sir i want coding for
    1
    12
    123
    1234
    12345

    ReplyDelete
    Replies
    1. Rush Hour TravelAugust 11, 2018 at 9:18 PM

      class pattern
      {
      public static void main(String args[])
      {
      int i,j,n;
      Scanner sc=new Scanner(System.in);
      System.out.println("enter the no:);
      n=sc.nextInt();
      for(i=0;i<n;i++)
      {
      for(j=0;j<i;j++)
      {
      System.out.printin(j+" ");
      }
      system.out.prin();
      }
      }

      Delete
  78. UnknownAugust 11, 2018 at 7:54 PM

    pls answer for this pattern
    n=5;
    15 10 6 3 1
    14 9 5 2
    13 8 4
    12 7
    11
    pls answer for this solution

    ReplyDelete
  79. RohanAugust 11, 2018 at 8:40 PM

    HELLO SIR CAN YOU PLEASE SEND ME THE CODE FOR:
    1
    2 9
    3 8 10
    4 7 11 14
    5 6 12 13 15

    ReplyDelete
  80. RohanAugust 11, 2018 at 8:40 PM

    HELLO SIR CAN YOU PLEASE SEND ME THE CODE FOR:
    1
    2 9
    3 8 10
    4 7 11 14
    5 6 12 13 15

    ReplyDelete
    Replies
    1. UnknownSeptember 11, 2018 at 9:45 PM

      sir, what about this pattern? what's the logic of it?

      Delete
  81. UnknownAugust 14, 2018 at 5:40 PM

    1
    121
    12321
    121
    1

    ReplyDelete
  82. UnknownAugust 14, 2018 at 7:50 PM

    sir please help me..
    input=6
    0utput=
    1 2 3 4 5 6
    13 14 15 16 17 18
    25 26 27 28 29 30
    31 32 33 34 35 36
    19 20 21 22 23 24
    7 8 9 10 11 12

    ReplyDelete
  83. UnknownAugust 14, 2018 at 7:51 PM

    sir please help me..
    input=6
    0utput=
    1 2 3 4 5 6
    13 14 15 16 17 18
    25 26 27 28 29 30
    31 32 33 34 35 36
    19 20 21 22 23 24
    7 8 9 10 11 12

    ReplyDelete
  84. AnonymousAugust 19, 2018 at 5:56 PM

    can any one tell how to print this sequence
    1
    12
    123
    1234
    12345

    ReplyDelete
  85. AnonymousAugust 19, 2018 at 8:33 PM

    ----5
    ---454
    --34543
    -2345432
    123454321

    where - is a space

    ReplyDelete
  86. UnknownAugust 20, 2018 at 5:41 PM

    Create A Flowchart That Will Print The Number From High To Low And Vice Versa.
    Sample Output: 5
    55555
    4444
    333
    22
    1
    1
    22
    333
    4444
    55555

    ReplyDelete
  87. UnknownAugust 22, 2018 at 12:16 PM

    1
    121
    12321
    121
    1

    ReplyDelete
  88. AnantAugust 22, 2018 at 1:00 PM

    Check out this for pattern printing in C https://www.programmingponds.com/2018/08/program-in-c-to-print-different-types.html

    ReplyDelete
  89. Krishna SrinivasanAugust 23, 2018 at 10:11 AM

    #include
    int main()
    {
    int i, j;
    int n=6;
    for(i=n;i>=1;i--)
    {
    for(j=1;j<=i;j++)
    {
    printf("%d",i);
    }
    printf("\n");
    }
    for(i=1;i<=n;i++)
    {
    for(j=1;j<=i;j++)
    {
    printf("%d",i);
    }
    printf("\n");
    }
    return 0;
    }

    ReplyDelete
  90. UnknownAugust 24, 2018 at 10:46 AM

    I need code of this
    333
    414
    525
    636
    333

    ReplyDelete
  91. samyuktaa balaAugust 25, 2018 at 10:30 AM

    1=1
    1+2=3
    1+2+3=6
    1+2+3+4=10
    1+2+3+4+5=15
    can anyone tell code for this

    ReplyDelete
  92. UnknownAugust 26, 2018 at 1:06 AM

    for n=4
    1 2 3 4
    9 10 11 12
    13 14 15 16
    5 6 7 8
    please give the short and effective logic for this

    ReplyDelete
  93. UnknownAugust 27, 2018 at 1:29 PM

    Code for above output

    1*2*3*10*11*12
    4*5*8*9
    6*7

    ReplyDelete
  94. AnonymousAugust 27, 2018 at 10:08 PM

    pattern :
    1
    2 4
    3 5 7
    6 8
    9
    please someone explain logic for the above pattern.

    ReplyDelete
  95. AnonymousAugust 28, 2018 at 7:04 PM

    Can I have code for below pattern
    1
    2*3
    4*5*6
    7*8*9*10
    7*8*9*10
    4*5*6
    2*3
    1

    ReplyDelete
    Replies
    1. Sujeet SinghAugust 31, 2018 at 3:28 PM

      This comment has been removed by the author.

      Delete
    2. UnknownSeptember 21, 2018 at 1:48 PM

      #include
      #include
      int main()
      {
      int n,i,temp,j,k=1,l,m;
      scanf("%d",&n);

      for(i=1 ; i<=n; i++)
      {
      for(j=1 ; j<=i ; j++)
      {
      printf("%d ",k);
      k++;
      if(i!=j)
      printf("*");

      }
      printf("\n");
      }
      k-= n;
      temp=k;
      for(i=n ; i>=1; i--)
      {
      for(j=1 ; j<=i ; j++)
      {
      printf("%d ",temp);
      temp++;
      if(i!=j)
      printf("*");
      }
      printf("\n");
      k-= (i-1);
      temp=k;

      }
      }

      Delete
  96. Sujeet SinghAugust 31, 2018 at 3:30 PM


    1
    2*3
    4*5*6
    7*8*9*10
    7*8*9*10
    4*5*6
    2*3
    1
    #include
    void print(int n)
    {
    for(int i = 1; i <= n; i++)
    {
    for(int j = 1; j < i+1; j++)
    {
    if(j < i)
    {
    printf("%d*",i);

    }
    else
    {
    printf("%d ",i);
    }
    }
    printf("\n");
    }
    for(int i = n; i >= 1; i--)
    {
    for(int j = 1; j < i+1; j++)
    {
    if(j < i)
    {
    printf("%d*",i);

    }

    else
    {
    printf("%d ",i);
    }
    }
    printf("\n");
    }
    }
    int main()
    {
    int n;
    scanf("%d",&n);
    print(n);
    return 0;
    }

    ReplyDelete
  97. AnonymousSeptember 1, 2018 at 5:18 PM

    1*2*3
    *4*5
    *6*
    7*
    8

    ReplyDelete
  98. UnknownSeptember 2, 2018 at 8:18 AM

    1
    2 9
    3 8 10
    4 7 11 14
    5 6 12 13 15

    Please solve this and explain the logic.

    ReplyDelete
  99. UnknownSeptember 2, 2018 at 10:59 AM

    input 3 output 123
    234
    345

    ReplyDelete
  100. UnknownSeptember 2, 2018 at 10:59 AM

    input 3 output 123
    234
    345

    ReplyDelete
  101. Sujeet SinghSeptember 3, 2018 at 2:34 PM

    3
    123
    234
    345

    #include

    int main() {
    //code
    int i,j,n,k,t=0;
    scanf("%d",&n);

    for(i=1;i<=n;i++)
    {
    t++;
    k=t;
    for(j=1;j<=n;j++)
    {
    printf("%d",k);
    k++;
    }
    printf("\n");
    }
    return 0;
    }

    ReplyDelete
  102. Sayan DeySeptember 3, 2018 at 10:57 PM

    This comment has been removed by the author.

    ReplyDelete
  103. AnonymousSeptember 4, 2018 at 10:13 AM

    how to print
    1
    141
    14941

    ReplyDelete
  104. TechDefinerSeptember 4, 2018 at 10:55 AM

    how to print 0
    12
    345
    6789
    Using two variables I,j only
    .

    ReplyDelete
  105. UnknownSeptember 5, 2018 at 12:04 PM

    how to print
    1
    2 7
    3 6 8
    4 5 9 10

    ReplyDelete
  106. UnknownSeptember 5, 2018 at 8:25 PM

    how to print
    1 2 3 4
    9 10 11 12
    13 14 15 16
    5 6 7 8

    ReplyDelete
    Replies
    1. Sujeet SinghSeptember 7, 2018 at 9:14 PM

      4
      1 2 3 4
      9 10 11 12
      13 14 15 16
      5 6 7 8
      CODE:
      #include
      void print(int n)
      {
      int i,j;
      int k=1;
      int m[n][n];
      for(i = 0; i < n; i++)
      {
      for(j = 0; j < n;j++)
      {
      m[i][j] = k++;
      }
      }
      for(i = 0; i < n; i++)
      {
      for(j = 0; j < n;j++)
      {
      if(i%2 == 0)
      {
      printf("%d ",m[i][j]);
      }
      }
      printf("\n");
      }
      for(i = n-1;i >= 0;i--)
      {
      for(j = 0; j < n; j++)

      {
      if(i%2 != 0)
      printf("%d ",m[i][j]);
      }
      printf("\n");
      }
      }
      int main()
      {
      int n;
      scanf("%d",&n);
      print(n);
      return 0;
      }

      Delete
  107. Sujeet SinghSeptember 6, 2018 at 2:02 PM

    1 2 3 4
    9 10 11 12
    13 14 15 16
    5 6 7 8

    void print(int n)
    {
    int i,j;
    int k=1;
    int m[n][n];
    for(i = 0; i < n; i++)
    {
    for(j = 0; j < n;j++)
    {
    m[i][j] = k++;
    }
    }
    for(i = 0; i < n; i++)
    {
    for(j = 0; j < n;j++)
    {
    if(i%2 == 0)
    {
    printf("%d ",m[i][j]);
    }
    }
    printf("\n");
    }
    for(i = n-1;i >= 0;i--)
    {
    for(j = 0; j < n; j++)

    {
    if(i%2 != 0)
    printf("%d ",m[i][j]);
    }
    printf("\n");
    }
    }
    int main()
    {
    int n;
    scanf("%d",&n);
    print(n);
    return 0;
    }

    ReplyDelete
  108. AnonymousSeptember 7, 2018 at 3:39 PM

    Hello Friends,
    How to write a code for this program? Please help me...

    1
    2 15 3
    4 5 66 6 7
    8 9 10 189 11 12 13
    .
    .

    ReplyDelete
  109. bSeptember 7, 2018 at 8:20 PM

    bro i need this pattern
    1
    2 4
    1 3 5
    2 4 6 8
    1 3 5 7 9
    2 4 6 8 10

    ReplyDelete
  110. Sujeet SinghSeptember 7, 2018 at 9:08 PM

    This comment has been removed by the author.

    ReplyDelete
  111. Sujeet SinghSeptember 7, 2018 at 9:10 PM

    I/P:
    6
    O/P:
    1
    2 4
    1 3 5
    2 4 6 8
    1 3 5 7 9
    2 4 6 8 10 12
    CODE:
    #include

    int main() {
    int n,i,j,k1,k2;
    scanf("%d",&n);

    for(i=0;i<=n;i++)
    {
    if(i%2!=0)
    {
    k1=1;
    for(j=0;j<i;j++)
    {
    printf("%d ",k1);
    k1+=2;;
    }
    }
    else
    {
    k2=2;
    for(j=0;j<i;j++)
    {
    printf("%d ",k2);
    k2+=2;
    }
    }
    printf("\n");
    }
    return 0;
    }

    ReplyDelete
  112. UnknownSeptember 8, 2018 at 6:29 PM

    1
    2 2
    3 3 3

    ReplyDelete
  113. AnonymousSeptember 8, 2018 at 6:59 PM

    Code for
    1×2××4×17×18×19×20
    --5×6×7×14×15×16
    ---8×9×12×13
    ----10×11

    ReplyDelete
  114. AnonymousSeptember 9, 2018 at 10:10 AM

    Pattern

    1
    2 6
    3 7 10
    4 8 11 13
    5 9 12 14 15

    ReplyDelete
  115. UnknownSeptember 11, 2018 at 5:09 AM

    Please Help--

    Input : n = 4
    Output :
    1
    3*2
    4*5*6
    10*9*8*7

    ReplyDelete
    Replies
    1. AnonymousSeptember 23, 2018 at 6:04 PM

      int main()
      {
      int i,j,n,count=0,k=0;
      printf("Enter N\n");
      scanf("%d",&n);
      for(i=1;i<=n;i++)
      {
      count=k;
      for(j=1;j<=i;j++)
      {
      if(i%2==0)
      {
      printf("%d",count+i);
      count=count-1;
      if(j!=i)
      printf("*");
      k++;
      }
      else
      {
      count=count+1;
      printf("%d",count);
      if(j!=i)
      printf("*");
      k++;
      }
      }
      printf("\n");
      }
      return 0;
      }

      Delete
  116. UnknownSeptember 11, 2018 at 9:15 PM

    Write a program for the pattern
    3
    5 5
    7 7 7
    9 9 9 9
    11 11 11 11 11

    ReplyDelete
  117. bhupesh bishtSeptember 12, 2018 at 7:34 PM

    This comment has been removed by the author.

    ReplyDelete
  118. rishabhSeptember 13, 2018 at 10:40 AM

    1
    1 1
    1 2 1
    1 3 3 1
    1 4 6 4 1
    1 5 10 10 5 1

    ReplyDelete
  119. UnknownSeptember 13, 2018 at 3:18 PM

    12345 67890
    1 5 6 0
    12345 67890
    1 678
    1 6 9

    how to print this

    ReplyDelete
  120. AnonymousSeptember 16, 2018 at 12:56 AM

    1*2*3*4*17*18*19*20
    5*6*7*14*15*16
    8*9*12*13
    10*11

    ReplyDelete
  121. VishuSeptember 16, 2018 at 5:18 PM










    1
    1 2 1
    1 2 3 2 1
    1 2 3 4 3 2 1
    1 2 3 4 5 4 3 2 1

    Anyone do this program please
    Early

    ReplyDelete
  122. UnknownSeptember 16, 2018 at 8:48 PM

    1 1
    12 21
    123 321
    1234321

    please solve this .

    ReplyDelete
  123. UnknownSeptember 18, 2018 at 9:24 AM

    ****5

    ***44

    **333

    *2222

    11111

    ReplyDelete
  124. UnknownSeptember 18, 2018 at 11:14 AM

    1
    1 1
    1 2 1
    1 3 3 1
    1 4 6 4 1
    1 5 10 10 5 1

    ReplyDelete
  125. UnknownSeptember 19, 2018 at 3:42 PM

    i need code for this pattern
    input:
    1*2*3*4*5
    11*12*13*14*15
    21*22*23*24*25
    16*17*18*19*20
    6*7*8*9*10

    this is top and bottom alternate pattern program.

    ReplyDelete
  126. UnknownSeptember 19, 2018 at 5:02 PM

    Could you help me with this pattern?
    9
    579
    13579
    1357913

    ReplyDelete
  127. AnonymousSeptember 22, 2018 at 6:08 AM

    Could any one help me in butterfly pattern?

    ReplyDelete
  128. Kalyan ChaitanyaSeptember 22, 2018 at 10:33 PM

    If n= 12
    1 2
    1 3 2
    1 4 3 5 2
    1 5 4 7 3 8 5 7 2

    ReplyDelete
  129. AnonymousSeptember 23, 2018 at 3:51 PM

    Can anyone tell how to print the following pattern?

    0
    10 12
    20 22 24
    30 32 34 36

    ReplyDelete
  130. UnknownSeptember 24, 2018 at 7:51 PM

    print in c pg

    12345
    54321
    12345
    54321
    12345
    54321

    ReplyDelete
  131. AnonymousSeptember 25, 2018 at 8:47 PM

    1
    3 1
    5 3 1
    7 5 3 1
    9 7 5 3 1
    Hw to print plz

    ReplyDelete
  132. AnonymousSeptember 25, 2018 at 8:48 PM

    1 2 3 4 5
    2 2 3 4 5
    3 3 3 4 5
    4 4 4 4 5
    5 5 5 5 5
    Hw to print plz

    ReplyDelete
  133. UnknownSeptember 26, 2018 at 11:13 AM

    Sir please send the code for this pattern
    1
    2 9
    3 8 10
    4 7 11 14
    5 6 12 13 15

    ReplyDelete
  134. UnknownSeptember 28, 2018 at 2:52 PM

    This comment has been removed by the author.

    ReplyDelete

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