Click on the series to view the code
1) 1 + 2 + 3 + 4 + 5 + ... + n
2) (1*1) + (2*2) + (3*3) + (4*4) + (5*5) + ... + (n*n)
3) (1) + (1+2) + (1+2+3) + (1+2+3+4) + ... + (1+2+3+4+...+n)
4) 1! + 2! + 3! + 4! + 5! + ... + n!
5) (1^1) + (2^2) + (3^3) + (4^4) + (5^5) + ... + (n^n)
6) (1!/1) + (2!/2) + (3!/3) + (4!/4) + (5!/5) + ... + (n!/n)
7) [(1^1)/1] + [(2^2)/2] + [(3^3)/3] + [(4^4)/4] + [(5^5)/5] + ... + [(n^n)/n]
8) [(1^1)/1!] + [(2^2)/2!] + [(3^3)/3!] + [(4^4)/4!] + [(5^5)/5!] + ... + [(n^n)/n!]
9) 1/2 - 2/3 + 3/4 - 4/5 + 5/6 - ...... n
10) 1 2 3 6 9 18 27 54...
11) 2 15 41 80 132 197 275 366 470 587
12) 1 3 8 15 27 50 92 169 311
Related Links:
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2/9 - 5/13 + 8/17 - 11/21 + 14/25..... upto n terms
ReplyDeletefor(i=1;i<=n;i++)
Delete{
sum+=((i*3)-1)/((4*i)+5);
}
can you plz help me to print the following series 1,5,15,34,65...
DeleteAttention everyone, the file provided above is not working. I have been looking for the working file and finally found it.
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.sdcccxxxcxxccx
Plz.... help to solve this problem
ReplyDeleteFind the sum of the series 5^2+ 〖10〗^2+ 〖15〗^(2 )+⋯
int sum=0,i;
Deletefor(i=1;i<n;i++)
{
sum=((5*i)exor(2));
print("%d + ",sum);
}
plz. solve it.
ReplyDelete1+3+5+7+.....+N
sum=0;
Deletefor(i=1;i<=n;i+=2)
sum+=i;
area of cicle ,reactangle .cylinder using swich statments
ReplyDeleteto generate the first n terms in the series --- 6,11,21,36,56,...
ReplyDeletea = 1;
Deleteb = 5
for (i=1; i<=n; i++)
{
printf("%d ",a+b);
b = b+5;
}
5 cannot be assumed it must got as input sir and btw wrong answer
Deletethen take input of x, start b = x and the b = b + x
Delete@Nimish Garg
DeleteThis program gives the sequence of 6,11,16,21,26 not 6,11,21,36,56
Change b= b+5 to b= b*i;
DeleteFor the series 1,2,3,6,9,18,27....
ReplyDeletethank u in advanc
http://cbasicprogram.blogspot.in/2013/01/series-program-10.html
DeleteWrite a program to generate the first n terms in the series --- 2,15,41,80,...
ReplyDeletethank you in advance..
int a=2,i,n=10;
Deletefor(i=1;i<=n;i++)
{
printf("%d ",a);
a+=13*i;
}
http://cbasicprogram.blogspot.com/2013/01/series-program-11.html
Deleteplz give me the code for 1,3,4,8,15,27
ReplyDelete1+(1+3)+(1+3+5)....
ReplyDelete#include
Deleteint main()
{
int b=2, ans=0, n, i=1, s=1;
printf("Enter number of terms\n");
scanf ("%d",&n);
printf("\n The series is: \n");
do
{
printf("%d \t",s);
ans = ans+s;
s = s+b;
b = b+1;
i = i + 1;
} while (i<=n);
printf ("\n The sum of the series is %d", ans);
return 0;
}
help me with this sequence: 110,24,1,3,9,2
ReplyDelete6 11 21 36 56 81
ReplyDeletea=6;
Deletefor(i=0;i<=5;i++)
{
a+=i*5;
printf("%d ",a);
}
sir, give me a general form.
DeleteFind sum of 1 + x + x2 + ... + xn without using pow()
ReplyDeletecalculate the sum of the n terms of the series s=1/2!+2/3!+3/4!+4/5!...
ReplyDeletei am also want this series,,,, if u have the program of this series plz sand meee....
Deleteplz help me the number sequence 120,99,80,65......
ReplyDeletecan anyone find sum of this series [x/1!+ x^2/2! +x^3/3! + x^4/4!+.......x^n/n!]
ReplyDeleteIN O(N) complexity
1*2+2*3+3*4+.....n*(n+1) help plss
ReplyDeletefor(i=1;i<n;i++)
Delete{
ans=i*(i+1);
printf("%d",ans);
}
please sir solve this questions
ReplyDeleteWrite a program in 'C' to compute the series :
(a) (x) + (x + n) + (x + n2) + (x + n3) + for a total of m terms. Where m, n and x are to
be accepted by the user.
(b) 1+5+11+17........n
S=1+a^2/3+a^4/15+a^6/35..a^n
ReplyDeletex^1/1+x^3/3+x^5/5+.....+X^n/n plz slove it
ReplyDeleteSir iska answer Mil Gaya ho to bta do
Delete2 + 5 + 9 + 19...provide code for this series pls...
ReplyDeletesir I want code for these number series 0 6 10 17 22 30 36
ReplyDeleteDo you find the code for the above series 0 6 10 17 22 30 36....
Delete1+(2/3!)+(3/5!)+(5/7!)+.....upto n terms
ReplyDelete2 6 12 20 30 Sir provide code for this series
ReplyDeleteCode for series 1,2,1,3,2,5,3,7,5,11,8...where eeven places should be fibonacci series and odd places should be prime numbers..if n=11 it should print 8
ReplyDeletePlz solve this 1²/2!+3²/4!+5²/6!+_____+n²/(n+1)!
ReplyDeleteGazab
ReplyDeleteto find nth element in the series
ReplyDelete0 0 7 6 14 12 21 18 28 24 35 30 ...........
#include
Deletemain()
{
int i,n,z,a=0,b=0;
printf("Enter the value of N= ");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
if(i%2==0)
{
z=a*6;
printf("%d,",z);
a++;
}
else
{
z=b*7;
printf("%d,",z);
b++;
}
}
return 0;
}
0 6 10 17 22 30 36....
ReplyDeletecan anyone find a logic for the above series.
#include
Deleteint main()
{
int n,i,x=0,y=6,z=0,k=0;
scanf("%d",&n);
printf("%d %d ",x,y);
for(i=2;i<n;i++)
{
if(i%2==0)
{
x=x+10+k;
printf("%d ",x);
k=k+2;
}
else
{
y=y+11+z;
printf("%d ",y);
z=z+2;
}
}
}
A complete website: The best site for C Programming. More than 500+ most popular, beginners friendly C programs that help you become an expert!
Deletehttps://www.cprogrammingplus.com/
1,3,7,13,19,25,27...
ReplyDeletecan anyone find the logic for above series?
Series for 6,7,12,14,18,21...
ReplyDelete1,2,1,3,2,5,3,7,5,11,8,13,13,17 find nth term
ReplyDelete2,3,6,11,18,27,38,51
ReplyDeleteWhat will the source code of this program?
Write a program to generate the following series - 10,5,60,15,110,--------
ReplyDelete#include
Deleteint main()
{
int n,i,a=10,b=5;
printf("Enter n value\n");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
if(i%2==0){
printf("%d ",b);
b+=10;
}
else
{
printf("%d ",a);
a+=50;
}
}
}
nice article for beginners.thank you.
ReplyDeletewelookups C++
javacodegeeks
1^0+2^2+3^3....n^n.
ReplyDeletehelp,how can sovle?give some tips.?
--121,,225,361,529---
ReplyDelete2 5 11 17 please helphow to solve this series
ReplyDelete6 9 14 21 30
ReplyDeletehow to solve
s
Deletewe want tis type of series program 7,5,8,6,9..... could u answer plz
ReplyDeleteint a=7,b=5,i,n;
Deletescanf("%d",&n);
printf("%d %d",a,b);
for(i=3;i<=n;i++)
{
if((i%2)==1)
{
a=a+1;
printf("%d",a);
}
else
{
b=b+1;
printf("%d",b);
}
}
//by SVR engineering college students,Nandyal
ReplyDelete#include
int main()
{
int i=3,j,k=5,n,a=0;
scanf("%d",&n);
for(j=1;j<=n;j++)
{
if(j==1)
a=0;
else if(j%2==0)//odd positions
{
k++;
a=a+k;
}
else//even positions
{
i++;
a=a+i;
}
printf(" %d ",a);
}
}
give the proramme for
ReplyDelete1
4 9
16 25 36
49 64 81 100
Thank you for sharing such knowledgeable post its not only helpful for the old but also new student for better preparation. I just share your post with my friends so that they can also read your post. C Language in Greater Noida.
ReplyDelete66 36 18 8
ReplyDeleteex- 6*6= 36
how to multiply this ?
can u help me with the series 6,9,14,21,30,41,54......
ReplyDelete1+4+9+16+25....
ReplyDeleteHelp me in the sequence
ReplyDelete0 6 10 17 22 30 36....
plz give me series of 10 5 60 15 110
ReplyDeletecan anyone help to solve this series using nested loop
ReplyDelete1 2 9 64 625
very knowledgable post sir your blog help me in programming. I am doing bca.
ReplyDelete1+4-9+16-25+...up to N solve it.
ReplyDelete3 7 4 12 8 20 12.... Can Any body solved this series
ReplyDeleteThanks for sharing this great info.,keep more sharing..
ReplyDeleteWeb Design and Development Bangalore | Web Designing Company In Bangalore | Web Development Company Bangalore | Web Design Company Bangalore
(5) Take an integer N as input from user. Write a program that will print following series upto Nth terms. 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, ……. please sove it with out useing condition .
ReplyDeleteWrite a C program to generate the following series 10, 5, 60, 15, 110….
ReplyDelete1+1/3+1/5+1/7+....+1/n( share code for this logic)
ReplyDeletehttps://www.csinfo360.com/p/series-programming-questions-and.html
ReplyDelete1-2+3-4+.....+n
ReplyDeleteThe program must print values starting at 9
ReplyDeleteUp to 911 (not including)
Incrementing by 5
Each line must print 6 numbers (last line can be less)
Each number must be formatted using a width of 7
Ques. Find the 15th term of the series?
ReplyDelete0,0,7,6,14,12,21,18, 28
Following series in c
ReplyDelete1, 7, 8, 15, 23 upto nth term, thanks in advance
20, 60, 104, 152, 204,…….please give me the code for this series
ReplyDeletenot there
Deletec program to generate the following series where N which is upper limit should be taken as an input. -1,0,2,5,10,17,28,41,58,81....N
ReplyDeletec program to generate the following series where N which is upper limit should be taken as an input. 5,35,96,190....N
Deletec program to generate the following series where N which is upper limit should be taken as an input. -1,1,5,11,19,29,41,55,71,89,109,155,181,209,239....N
ReplyDeletec program to generate the following series where N which is upper limit should be taken as an input. 1,-2,6,-15,31,-56....N can please send the code
ReplyDeletef=n!(1+(1/3)+...... (1/n))
ReplyDeletehttps://maytinhtrananh.vn/sua-may-tinh-may-in.html
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Please solve it::find the sum of the given series =1+3+6+9+...... N.
ReplyDelete1,-3,5,-7,9,-11,13,-15........
ReplyDeleteplease solve it;;sum of first N th terms for following series
https://phalephongthuy.top/category/cup-vinh-danh/
ReplyDeleteC program that generates the following series.
ReplyDeletei) 1 3 3 9 27 243 6561
ii) 1 2 4 10 42 422 17726
A complete website: The best site for C Programming. More than 500+ most popular, beginners friendly C programs that help you become an expert!
Deletehttps://www.cprogrammingplus.com/
Cúp pha lê với thiết kế mỹ thuật sẽ là món quà tặng lưu niệm sang trọng và ý nghĩa để tôn vinh những nhà vô địch hoặc ghi nhận công lao đóng góp của những thành viên Xuất sắc có những đóng góp và cống hiến cho cơ quan, tổ chức
ReplyDeletePha lê 3d quà tặng độc đáo với công nghệ khắc lizer 2d, 3d các hình ảnh đồ vật, hình công ty, nhà máy. Công nghệ khắc hình Pha lê 3D trong khối pha lê đang là "mốt" ở nhiều nước châu Âu và một số nước châu Á. Đây là dòng sản phẩm cao cấp được khắc hình ở giữa nhờ công nghệ khắc tia laser tiên tiến (có thể đưa bất cứ hình ảnh nào vào giữa khối pha lê). Đủ loại hình khối pha lê được gọt giũa theo yêu cầu của khách hàng, đủ kiểu hình ảnh chân dung, gia đình... nằm gọn trong khối pha lê đẹp đến lung linh.
Cúp pha lê là phần thưởng tôn vinh người chiến thắng, khích lệ tinh thần, thành quả nỗ lực đạt được. Cúp vinh danh phải toát ra được sự tinh tế trong đó, là món quà tặng dành cho người xứng đáng. Các mẫu cúp ngôi sao, cúp bóng đá, cúp doanh nghiệp hiện này được sử dụng nhiều.
ReplyDeleteCúp pha lê là sản phẩm cúp sang trọng được công ty chúng tôi sử dụng chất liệu là pha lê cao cấp để sản xuất ra chúng. Cúp pha lê có thể sử dụng làm các cúp giải thưởng cho các chương trình, các cuộc thi, hoặc là dùng để tặng tri ân khách hàng, cán bộ công nhân viên trong công ty. Ngoài ra tặng phẩm pha lê còn có dùng làm vật trang trí trong nhà rất là đẹp mắt. Chúng tôi là công ty chuyên sản xuất quà tặng tôn vinh cao cấp với nhiều năm kinh nghiệm, đội ngũ công nhân lành nghề, và một đội ngũ thiết kế tâm thuyết, với khát vọng trở thành công ty hàng đầu về quà tặng, chúng tôi đã và đang nỗ lực hơn trong từng sản phẩm gửi tới khách hàng hãy liên hệ với chúng tôi để có được báo giá tốt nhất.
ReplyDeleteHow to generate the series :
ReplyDeletex+x^2/3-x^3/4+x^4/5-x^5/6+x^6/7-x^7/8+x^8/9-............. n terms
How to generate the series :
ReplyDeletex+x^2/3-x^3/4+x^4/5-x^5/6+x^6/7-x^7/8+x^8/9-............. n terms
How to generate the series :
ReplyDeletex+x^2/3-x^3/4+x^4/5-x^5/6+x^6/7-x^7/8+x^8/9-............. n terms
can you pls give me program for the sequence for 20 , 60 , 104 , 152 , 204 , .......
ReplyDeleteplease code this series
ReplyDelete1, 9, 17, 33, 49, 73, 97
This comment has been removed by the author.
ReplyDeletei need the same code for this series 1,9,17,33,49,73,97
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ReplyDeleteCúp golf được coi là sản phẩm sang trọng nhất hiện nay
A complete website:
ReplyDeletehttps://www.cprogrammingplus.com/
can you plz help me to solve the series 1 4 27 256 ....
ReplyDeleteWrite a program on c++ compute the sum, 𝑆=1+2+4+7+11+⋯+56
ReplyDeleteFor Complete explanation of C++ please visit - SchoolingAxis
ReplyDeleteGenerate Following series up to given steps :- 0,1,1,2,3,5,8,13,21,34,.....
ReplyDeleteGenerate following series
ReplyDeletefor N=3 series:- 1 2 1 3 2 1
for N=5 Series:- 1 2 1 3 2 1 4 3 2 1 5 4 3 2 1
s=-x+x^3/3-x^5/5+x^7/7
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