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#include<stdio.h>
int main()
{
int i,j,k;
k=1;
for(i=1;i<=5;i+=2)
{
for(j=5;j>=1;j--)
{
if(j>i)
printf(" ");
else
printf("%d ",k++);
}
printf("\n");
}
return 0;
}
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#include
ReplyDeleteint main()
{
int i, j, n=1;
for(i=1; i<=5; i+=2)
{
for(j=5; j>=i; j-=2)
{
printf(" ");
}
for(j=1; j<=i; ++j)
{
printf("%2d", n++);
}
printf("\n");
}
return 0;
}
#include
ReplyDeleteusing namespace std;
int main()
{
int n,k;
cout<<"enter order:"<>n;
for(int i=n;i>=1;i--){
k=i-1;
while(k){
cout<<" ";
k--;
}
for(int j=n;j>=i;j--){
cout<<"*"<<" ";
}
cout<<endl;
}
return 0;
}
not the required code
Deletefunction pattern7(){
ReplyDeletevar some=value-1;
var start=1;
var one=1;
//
for(var i=1;i <= value;i++){
for(var k=1;k <= some;k++){
document.write('  ');
}
some--;
//new_one++;
for(var j=1;j <= (2*i)-1;j++){
document.write(' ');
document.write(one);
one=one+1;
}
//start=j;
document.write('
');
}
}
#include
ReplyDelete#include
void main()
{
int i,j,k=1;
for(i=4;i>=0;i-=2
{
for(j=0;j<=4;j++)
{
if(j<i)
{
printf(" ");
}
else
{
printf("%d ",k);
k++;
}
}
printf("\n");
}
getch();
}
any one help me how to do with i and j value only
ReplyDeleteThose who posted their codes will have done it with only two variable, i and j. That's the goal. To use less variable as possible and make sure the program works for any kind of number.
Deleteint main()
ReplyDelete{
int i, j, k;
int m = 1;
for (i = 1; i <= 3; i++)
{
for (j = i; j < 3; j++)
{
printf(" ");
printf(" ");
}
for (k = 1; k < (i * 2); k++)
{
printf("%d",m);
printf(" ");
m += 1;
}
printf("\n");
}
return 0;
}
#include
ReplyDeleteint main()
{
int r,i,j,k,s;
printf("Enter the no. of rows : ");
scanf("%d",&r);
for(i=1,k=1;i<=r;i++)
{
for(s=1;s<=r-i;s++)
{
printf(" ");
}
for(j=1;j<=(2*i)-1;j++,k++)
{
printf("%d ",k);
}
printf("\n");
}
}
#include
ReplyDelete#include
#include
int main(){
int i,j,k;
for(i=1;i<=3;i++){
for(k=3-i;k>=1;k--){
printf(" ");
}
for(j=(i*i-2*i+2);j<=i*i;j++){
printf("%d ",j);
}
printf("\n");
}
}
Code is correct if we put space before %d.
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