1
2*2
3*3*3
4*4*4*4
4*4*4*4
3*3*3
2*2
1
#include<stdio.h>
int main()
{
int i,j;
for(i=1;i<=4;i++)
{
for(j=1;j<=i;j++)
{
if(j<i)
printf("%d*",i);
else
printf("%d",i);
}
printf(" \n");
}
for(i=4;i>=1;i--)
{
for(j=1;j<=i;j++)
{
if(j<i)
printf("%d*",i);
else
printf("%d",i);
}
printf(" \n");
}
return 0;
}
Related Links:
- More Number Pattern Programs
- Star Pattern Programs in C
- Alphabet Pattern Programs in C
- Series Programs in C
following is the small modification of above program
ReplyDeletefor(i=1;i<=4;i++)
{
for(j=1;j<=i;j++)
{
if(j!=1)
printf("%d*",i);
else
printf("%d",i);
}
printf(" \n");
}
vooooooo
Delete//program to print the following pattern:
Delete// 1
// 2 * 2
// 3 * 3 * 3
// 4 * 4 * 4 * 4
// 4 * 4 * 4 * 4
// 3 * 3 * 3
// 2 * 2
// 1
#include
int main()
{
int k=1, m=1;
for(int i=1; i<=8; i++)
{
int x;
if(i>=1&&i<=4)
x=i;
else //(i>=5&&i<=8)
x= i-m;
for(int j=1; j<=7; j++)
{
if(j>=1&&j<=k)
{
if(j%2==0)
printf("* ");
else
printf("%d ", x);
}
}
printf("\n");
if(i<=3)
k +=2;
else if(i>=5)
{
k -=2;
m +=2;
}
}
return 0;
}
#include
ReplyDeleteint main()
{
int r,i,j;
printf("Enter the no. of rows : ");
scanf("%d",&r);
for(i=1;i<=r;i++)
{
for(j=1;j<=i;j++)
{
printf("%d",i);
if(j!=i)
{
printf("*");
}
}
printf("\n");
}
for(i=r;i>=1;i--)
{
for(j=1;j<=i;j++)
{
printf("%d",i);
if(j!=i)
{
printf("*");
}
}
printf("\n");
}
return 0;
}
#include <stdio.h>
ReplyDeletevoid main()
{
int i,j;
for(i=1;i<=4;i++)
{
for(j=1;j<=i;j++)
{ if(j==i)
printf("%d",i);
else
printf("%d*",i);
}
printf("\n");
}
for(i=4;i>=1;i--)
{
for(j=i;j>=1;j--)
{ if(j==i)
printf("%d",i);
else
printf("*%d",i);
}
printf("\n");
}
}
terfbipiazu Shawn Platt https://www.comewrite.net/profile/Nilabviewactivationcodecrack-BETTER/profile
ReplyDeletedispcamising