**Click on the series to view the code**

1) 1 + 2 + 3 + 4 + 5 + ... + n

2) (1*1) + (2*2) + (3*3) + (4*4) + (5*5) + ... + (n*n)

3) (1) + (1+2) + (1+2+3) + (1+2+3+4) + ... + (1+2+3+4+...+n)

4) 1! + 2! + 3! + 4! + 5! + ... + n!

5) (1^1) + (2^2) + (3^3) + (4^4) + (5^5) + ... + (n^n)

6) (1!/1) + (2!/2) + (3!/3) + (4!/4) + (5!/5) + ... + (n!/n)

7) [(1^1)/1] + [(2^2)/2] + [(3^3)/3] + [(4^4)/4] + [(5^5)/5] + ... + [(n^n)/n]

8) [(1^1)/1!] + [(2^2)/2!] + [(3^3)/3!] + [(4^4)/4!] + [(5^5)/5!] + ... + [(n^n)/n!]

9) 1/2 - 2/3 + 3/4 - 4/5 + 5/6 - ...... n

10) 1 2 3 6 9 18 27 54...

11) 2 15 41 80 132 197 275 366 470 587

12) 1 3 8 15 27 50 92 169 311

**Related Links:**

- Number Pattern Programs

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- Alphabet Pattern Programs in C

2/9 - 5/13 + 8/17 - 11/21 + 14/25..... upto n terms

ReplyDeletefor(i=1;i<=n;i++)

Delete{

sum+=((i*3)-1)/((4*i)+5);

}

very nice

Deletecan you plz help me to print the following series 1,5,15,34,65...

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.sdcccxxxcxxccx

A complete website: The best site for C Programming. More than 500+ most popular, beginners friendly C programs that help you become an expert!

Deletehttps://www.cprogrammingplus.com/

Plz.... help to solve this problem

ReplyDeleteFind the sum of the series 5^2+ 〖10〗^2+ 〖15〗^(2 )+⋯

int sum=0,i;

Deletefor(i=1;i<n;i++)

{

sum=((5*i)exor(2));

print("%d + ",sum);

}

plz. solve it.

ReplyDelete1+3+5+7+.....+N

sum=0;

Deletefor(i=1;i<=n;i+=2)

sum+=i;

area of cicle ,reactangle .cylinder using swich statments

ReplyDeleteto generate the first n terms in the series --- 6,11,21,36,56,...

ReplyDeletea = 1;

Deleteb = 5

for (i=1; i<=n; i++)

{

printf("%d ",a+b);

b = b+5;

}

5 cannot be assumed it must got as input sir and btw wrong answer

Deletethen take input of x, start b = x and the b = b + x

Delete@Nimish Garg

DeleteThis program gives the sequence of 6,11,16,21,26 not 6,11,21,36,56

Change b= b+5 to b= b*i;

DeleteFor the series 1,2,3,6,9,18,27....

ReplyDeletethank u in advanc

http://cbasicprogram.blogspot.in/2013/01/series-program-10.html

DeleteWrite a program to generate the first n terms in the series --- 2,15,41,80,...

ReplyDeletethank you in advance..

int a=2,i,n=10;

Deletefor(i=1;i<=n;i++)

{

printf("%d ",a);

a+=13*i;

}

http://cbasicprogram.blogspot.com/2013/01/series-program-11.html

Deleteplz give me the code for 1,3,4,8,15,27

ReplyDelete1+(1+3)+(1+3+5)....

ReplyDelete#include

Deleteint main()

{

int b=2, ans=0, n, i=1, s=1;

printf("Enter number of terms\n");

scanf ("%d",&n);

printf("\n The series is: \n");

do

{

printf("%d \t",s);

ans = ans+s;

s = s+b;

b = b+1;

i = i + 1;

} while (i<=n);

printf ("\n The sum of the series is %d", ans);

return 0;

}

help me with this sequence: 110,24,1,3,9,2

ReplyDelete6 11 21 36 56 81

ReplyDeletea=6;

Deletefor(i=0;i<=5;i++)

{

a+=i*5;

printf("%d ",a);

}

sir, give me a general form.

DeleteFind sum of 1 + x + x2 + ... + xn without using pow()

ReplyDeletecalculate the sum of the n terms of the series s=1/2!+2/3!+3/4!+4/5!...

ReplyDeletei am also want this series,,,, if u have the program of this series plz sand meee....

Deleteplz help me the number sequence 120,99,80,65......

ReplyDeletecan anyone find sum of this series [x/1!+ x^2/2! +x^3/3! + x^4/4!+.......x^n/n!]

ReplyDeleteIN O(N) complexity

1*2+2*3+3*4+.....n*(n+1) help plss

ReplyDeletefor(i=1;i<n;i++)

Delete{

ans=i*(i+1);

printf("%d",ans);

}

please sir solve this questions

ReplyDeleteWrite a program in 'C' to compute the series :

(a) (x) + (x + n) + (x + n2) + (x + n3) + for a total of m terms. Where m, n and x are to

be accepted by the user.

(b) 1+5+11+17........n

S=1+a^2/3+a^4/15+a^6/35..a^n

ReplyDeletex^1/1+x^3/3+x^5/5+.....+X^n/n plz slove it

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Delete2 + 5 + 9 + 19...provide code for this series pls...

ReplyDeletesir I want code for these number series 0 6 10 17 22 30 36

ReplyDeleteDo you find the code for the above series 0 6 10 17 22 30 36....

Delete1+(2/3!)+(3/5!)+(5/7!)+.....upto n terms

ReplyDelete2 6 12 20 30 Sir provide code for this series

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ReplyDeleteto find nth element in the series

ReplyDelete0 0 7 6 14 12 21 18 28 24 35 30 ...........

#include

Deletemain()

{

int i,n,z,a=0,b=0;

printf("Enter the value of N= ");

scanf("%d",&n);

for(i=1;i<=n;i++)

{

if(i%2==0)

{

z=a*6;

printf("%d,",z);

a++;

}

else

{

z=b*7;

printf("%d,",z);

b++;

}

}

return 0;

}

Adu Ayam Pisau

ReplyDelete0 6 10 17 22 30 36....

ReplyDeletecan anyone find a logic for the above series.

#include

Deleteint main()

{

int n,i,x=0,y=6,z=0,k=0;

scanf("%d",&n);

printf("%d %d ",x,y);

for(i=2;i<n;i++)

{

if(i%2==0)

{

x=x+10+k;

printf("%d ",x);

k=k+2;

}

else

{

y=y+11+z;

printf("%d ",y);

z=z+2;

}

}

}

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1,3,7,13,19,25,27...

ReplyDeletecan anyone find the logic for above series?

Series for 6,7,12,14,18,21...

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2,3,6,11,18,27,38,51

ReplyDeleteWhat will the source code of this program?

tarung sampai mati

ReplyDeleteWrite a program to generate the following series - 10,5,60,15,110,--------

ReplyDelete#include

Deleteint main()

{

int n,i,a=10,b=5;

printf("Enter n value\n");

scanf("%d",&n);

for(i=1;i<=n;i++)

{

if(i%2==0){

printf("%d ",b);

b+=10;

}

else

{

printf("%d ",a);

a+=50;

}

}

}

nice article for beginners.thank you.

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javacodegeeks

1^0+2^2+3^3....n^n.

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--121,,225,361,529---

ReplyDelete2 5 11 17 please helphow to solve this series

ReplyDelete6 9 14 21 30

ReplyDeletehow to solve

s

Deletewe want tis type of series program 7,5,8,6,9..... could u answer plz

ReplyDeleteint a=7,b=5,i,n;

Deletescanf("%d",&n);

printf("%d %d",a,b);

for(i=3;i<=n;i++)

{

if((i%2)==1)

{

a=a+1;

printf("%d",a);

}

else

{

b=b+1;

printf("%d",b);

}

}

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ReplyDelete#include

int main()

{

int i=3,j,k=5,n,a=0;

scanf("%d",&n);

for(j=1;j<=n;j++)

{

if(j==1)

a=0;

else if(j%2==0)//odd positions

{

k++;

a=a+k;

}

else//even positions

{

i++;

a=a+i;

}

printf(" %d ",a);

}

}

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Deletehttps://www.cprogrammingplus.com/

give the proramme for

ReplyDelete1

4 9

16 25 36

49 64 81 100

Thank you for sharing such knowledgeable post its not only helpful for the old but also new student for better preparation. I just share your post with my friends so that they can also read your post. C Language in Greater Noida.

ReplyDelete66 36 18 8

ReplyDeleteex- 6*6= 36

how to multiply this ?

can u help me with the series 6,9,14,21,30,41,54......

ReplyDelete1+4+9+16+25....

ReplyDeleteHelp me in the sequence

ReplyDelete0 6 10 17 22 30 36....

plz give me series of 10 5 60 15 110

ReplyDeletecan anyone help to solve this series using nested loop

ReplyDelete1 2 9 64 625

very knowledgable post sir your blog help me in programming. I am doing bca.

ReplyDelete1+4-9+16-25+...up to N solve it.

ReplyDelete3 7 4 12 8 20 12.... Can Any body solved this series

ReplyDeleteThanks for sharing this great info.,keep more sharing..

ReplyDeleteWeb Design and Development Bangalore|Web Designing Company In Bangalore|Web Development Company Bangalore|Web Design Company Bangalore(5) Take an integer N as input from user. Write a program that will print following series upto Nth terms. 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, ……. please sove it with out useing condition .

ReplyDeleteWrite a C program to generate the following series 10, 5, 60, 15, 110….

ReplyDelete1+1/3+1/5+1/7+....+1/n( share code for this logic)

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1-2+3-4+.....+n

ReplyDeleteThe program must print values starting at 9

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Incrementing by 5

Each line must print 6 numbers (last line can be less)

Each number must be formatted using a width of 7

Ques. Find the 15th term of the series?

ReplyDelete0,0,7,6,14,12,21,18, 28

Following series in c

ReplyDelete1, 7, 8, 15, 23 upto nth term, thanks in advance

20, 60, 104, 152, 204,…….please give me the code for this series

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Deletec program to generate the following series where N which is upper limit should be taken as an input. -1,0,2,5,10,17,28,41,58,81....N

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c program to generate the following series where N which is upper limit should be taken as an input. -1,1,5,11,19,29,41,55,71,89,109,155,181,209,239....N

ReplyDeletec program to generate the following series where N which is upper limit should be taken as an input. 1,-2,6,-15,31,-56....N can please send the code

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ReplyDeletei) 1 3 3 9 27 243 6561

ii) 1 2 4 10 42 422 17726

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Cúp pha lê

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ReplyDeleteHow to generate the series :

ReplyDeletex+x^2/3-x^3/4+x^4/5-x^5/6+x^6/7-x^7/8+x^8/9-............. n terms

How to generate the series :

ReplyDeletex+x^2/3-x^3/4+x^4/5-x^5/6+x^6/7-x^7/8+x^8/9-............. n terms

How to generate the series :

ReplyDeletex+x^2/3-x^3/4+x^4/5-x^5/6+x^6/7-x^7/8+x^8/9-............. n terms

https://www.cprogrammingplus.com/

can you pls give me program for the sequence for 20 , 60 , 104 , 152 , 204 , .......

ReplyDeleteplease code this series

ReplyDelete1, 9, 17, 33, 49, 73, 97

This comment has been removed by the author.

ReplyDeletei need the same code for this series 1,9,17,33,49,73,97

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can you plz help me to solve the series 1 4 27 256 ....

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Write a program on c++ compute the sum, 𝑆=1+2+4+7+11+⋯+56

ReplyDelete