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Series Program

121 comments:

  1. 2/9 - 5/13 + 8/17 - 11/21 + 14/25..... upto n terms

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    Replies
    1. for(i=1;i<=n;i++)
      {
      sum+=((i*3)-1)/((4*i)+5);
      }

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    2. can you plz help me to print the following series 1,5,15,34,65...

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    3. Attention everyone, the file provided above is not working. I have been looking for the working file and finally found it.



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      .cx
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      .sdcccxxxcxxccx

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  2. Plz.... help to solve this problem
    Find the sum of the series 5^2+ 〖10〗^2+ 〖15〗^(2 )+⋯

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    Replies
    1. int sum=0,i;
      for(i=1;i<n;i++)
      {
      sum=((5*i)exor(2));
      print("%d + ",sum);
      }

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  3. area of cicle ,reactangle .cylinder using swich statments

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  4. to generate the first n terms in the series --- 6,11,21,36,56,...

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    Replies
    1. a = 1;
      b = 5
      for (i=1; i<=n; i++)
      {
      printf("%d ",a+b);
      b = b+5;
      }

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    2. 5 cannot be assumed it must got as input sir and btw wrong answer

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    3. then take input of x, start b = x and the b = b + x

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    4. @Nimish Garg
      This program gives the sequence of 6,11,16,21,26 not 6,11,21,36,56

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  5. For the series 1,2,3,6,9,18,27....
    thank u in advanc

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    Replies
    1. http://cbasicprogram.blogspot.in/2013/01/series-program-10.html

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  6. Write a program to generate the first n terms in the series --- 2,15,41,80,...
    thank you in advance..

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    Replies
    1. int a=2,i,n=10;
      for(i=1;i<=n;i++)
      {
      printf("%d ",a);
      a+=13*i;
      }

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    2. http://cbasicprogram.blogspot.com/2013/01/series-program-11.html

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  7. plz give me the code for 1,3,4,8,15,27

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  8. Replies
    1. #include
      int main()
      {
      int b=2, ans=0, n, i=1, s=1;
      printf("Enter number of terms\n");
      scanf ("%d",&n);
      printf("\n The series is: \n");
      do
      {
      printf("%d \t",s);
      ans = ans+s;
      s = s+b;
      b = b+1;
      i = i + 1;
      } while (i<=n);
      printf ("\n The sum of the series is %d", ans);
      return 0;
      }

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  9. help me with this sequence: 110,24,1,3,9,2

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  10. Find sum of 1 + x + x2 + ... + xn without using pow()

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  11. calculate the sum of the n terms of the series s=1/2!+2/3!+3/4!+4/5!...

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    Replies
    1. i am also want this series,,,, if u have the program of this series plz sand meee....

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  12. plz help me the number sequence 120,99,80,65......

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  13. can anyone find sum of this series [x/1!+ x^2/2! +x^3/3! + x^4/4!+.......x^n/n!]
    IN O(N) complexity

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  14. 1*2+2*3+3*4+.....n*(n+1) help plss

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    Replies
    1. for(i=1;i<n;i++)
      {
      ans=i*(i+1);
      printf("%d",ans);
      }

      Delete
  15. please sir solve this questions

    Write a program in 'C' to compute the series :
    (a) (x) + (x + n) + (x + n2) + (x + n3) + for a total of m terms. Where m, n and x are to
    be accepted by the user.
    (b) 1+5+11+17........n

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  16. x^1/1+x^3/3+x^5/5+.....+X^n/n plz slove it

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  17. 2 + 5 + 9 + 19...provide code for this series pls...

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  18. sir I want code for these number series 0 6 10 17 22 30 36

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    Replies
    1. Do you find the code for the above series 0 6 10 17 22 30 36....

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  19. 1+(2/3!)+(3/5!)+(5/7!)+.....upto n terms

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  20. 2 6 12 20 30 Sir provide code for this series

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  21. Code for series 1,2,1,3,2,5,3,7,5,11,8...where eeven places should be fibonacci series and odd places should be prime numbers..if n=11 it should print 8

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  22. Plz solve this 1²/2!+3²/4!+5²/6!+_____+n²/(n+1)!

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  23. to find nth element in the series
    0 0 7 6 14 12 21 18 28 24 35 30 ...........

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    Replies
    1. #include
      main()
      {
      int i,n,z,a=0,b=0;
      printf("Enter the value of N= ");
      scanf("%d",&n);
      for(i=1;i<=n;i++)
      {
      if(i%2==0)
      {
      z=a*6;
      printf("%d,",z);
      a++;
      }
      else
      {
      z=b*7;
      printf("%d,",z);
      b++;
      }
      }
      return 0;
      }

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  24. 0 6 10 17 22 30 36....
    can anyone find a logic for the above series.

    ReplyDelete
    Replies
    1. #include
      int main()
      {
      int n,i,x=0,y=6,z=0,k=0;
      scanf("%d",&n);
      printf("%d %d ",x,y);
      for(i=2;i<n;i++)
      {
      if(i%2==0)
      {
      x=x+10+k;
      printf("%d ",x);
      k=k+2;
      }
      else
      {
      y=y+11+z;
      printf("%d ",y);
      z=z+2;
      }
      }
      }

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    2. A complete website: The best site for C Programming. More than 500+ most popular, beginners friendly C programs that help you become an expert!
      https://www.cprogrammingplus.com/

      Delete
  25. 1,3,7,13,19,25,27...
    can anyone find the logic for above series?

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  26. 1,2,1,3,2,5,3,7,5,11,8,13,13,17 find nth term

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  27. 2,3,6,11,18,27,38,51
    What will the source code of this program?

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  28. Write a program to generate the following series - 10,5,60,15,110,--------

    ReplyDelete
    Replies
    1. KALAVALA SAI NAGA BHAVANASeptember 21, 2020 at 9:25 PM

      #include
      int main()
      {

      int n,i,a=10,b=5;
      printf("Enter n value\n");
      scanf("%d",&n);

      for(i=1;i<=n;i++)
      {
      if(i%2==0){
      printf("%d ",b);
      b+=10;
      }
      else
      {
      printf("%d ",a);
      a+=50;
      }
      }
      }

      Delete
  29. 1^0+2^2+3^3....n^n.
    help,how can sovle?give some tips.?

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  30. 2 5 11 17 please helphow to solve this series

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  31. we want tis type of series program 7,5,8,6,9..... could u answer plz



    ReplyDelete
    Replies
    1. int a=7,b=5,i,n;
      scanf("%d",&n);
      printf("%d %d",a,b);
      for(i=3;i<=n;i++)
      {
      if((i%2)==1)
      {
      a=a+1;
      printf("%d",a);
      }
      else
      {
      b=b+1;
      printf("%d",b);
      }
      }

      Delete
  32. //by SVR engineering college students,Nandyal
    #include
    int main()
    {
    int i=3,j,k=5,n,a=0;
    scanf("%d",&n);
    for(j=1;j<=n;j++)
    {
    if(j==1)
    a=0;
    else if(j%2==0)//odd positions
    {
    k++;
    a=a+k;
    }
    else//even positions
    {
    i++;
    a=a+i;
    }
    printf(" %d ",a);
    }
    }

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  33. give the proramme for
    1
    4 9
    16 25 36
    49 64 81 100

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  34. Thank you for sharing such knowledgeable post its not only helpful for the old but also new student for better preparation. I just share your post with my friends so that they can also read your post. C Language in Greater Noida.

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  35. 66 36 18 8
    ex- 6*6= 36
    how to multiply this ?

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  36. can u help me with the series 6,9,14,21,30,41,54......

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  37. Help me in the sequence
    0 6 10 17 22 30 36....

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  38. plz give me series of 10 5 60 15 110

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  39. can anyone help to solve this series using nested loop
    1 2 9 64 625

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  40. very knowledgable post sir your blog help me in programming. I am doing bca.

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  41. 1+4-9+16-25+...up to N solve it.

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  42. 3 7 4 12 8 20 12.... Can Any body solved this series

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  43. (5) Take an integer N as input from user. Write a program that will print following series upto Nth terms. 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, ……. please sove it with out useing condition .

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  44. Write a C program to generate the following series 10, 5, 60, 15, 110….

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  45. 1+1/3+1/5+1/7+....+1/n( share code for this logic)

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  46. https://www.csinfo360.com/p/series-programming-questions-and.html

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  47. The program must print values starting at 9
    Up to 911 (not including)
    Incrementing by 5
    Each line must print 6 numbers (last line can be less)
    Each number must be formatted using a width of 7

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  48. Ques. Find the 15th term of the series?

    0,0,7,6,14,12,21,18, 28

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  49. Following series in c
    1, 7, 8, 15, 23 upto nth term, thanks in advance

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  50. 20, 60, 104, 152, 204,…….please give me the code for this series

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  51. c program to generate the following series where N which is upper limit should be taken as an input. -1,0,2,5,10,17,28,41,58,81....N

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    Replies
    1. c program to generate the following series where N which is upper limit should be taken as an input. 5,35,96,190....N

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  52. c program to generate the following series where N which is upper limit should be taken as an input. -1,1,5,11,19,29,41,55,71,89,109,155,181,209,239....N

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  53. c program to generate the following series where N which is upper limit should be taken as an input. 1,-2,6,-15,31,-56....N can please send the code

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  54. f=n!(1+(1/3)+...... (1/n))

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  55. Please solve it::find the sum of the given series =1+3+6+9+...... N.

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  56. 1,-3,5,-7,9,-11,13,-15........

    please solve it;;sum of first N th terms for following series

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  57. C program that generates the following series.
    i) 1 3 3 9 27 243 6561
    ii) 1 2 4 10 42 422 17726

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    Replies
    1. A complete website: The best site for C Programming. More than 500+ most popular, beginners friendly C programs that help you become an expert!
      https://www.cprogrammingplus.com/

      Delete
  58. Cúp pha lê với thiết kế mỹ thuật sẽ là món quà tặng lưu niệm sang trọng và ý nghĩa để tôn vinh những nhà vô địch hoặc ghi nhận công lao đóng góp của những thành viên Xuất sắc có những đóng góp và cống hiến cho cơ quan, tổ chức
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  59. Cúp pha lê là phần thưởng tôn vinh người chiến thắng, khích lệ tinh thần, thành quả nỗ lực đạt được. Cúp vinh danh phải toát ra được sự tinh tế trong đó, là món quà tặng dành cho người xứng đáng. Các mẫu cúp ngôi sao, cúp bóng đá, cúp doanh nghiệp hiện này được sử dụng nhiều.

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  60. Cúp pha lê là sản phẩm cúp sang trọng được công ty chúng tôi sử dụng chất liệu là pha lê cao cấp để sản xuất ra chúng. Cúp pha lê có thể sử dụng làm các cúp giải thưởng cho các chương trình, các cuộc thi, hoặc là dùng để tặng tri ân khách hàng, cán bộ công nhân viên trong công ty. Ngoài ra tặng phẩm pha lê còn có dùng làm vật trang trí trong nhà rất là đẹp mắt. Chúng tôi là công ty chuyên sản xuất quà tặng tôn vinh cao cấp với nhiều năm kinh nghiệm, đội ngũ công nhân lành nghề, và một đội ngũ thiết kế tâm thuyết, với khát vọng trở thành công ty hàng đầu về quà tặng, chúng tôi đã và đang nỗ lực hơn trong từng sản phẩm gửi tới khách hàng hãy liên hệ với chúng tôi để có được báo giá tốt nhất.

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  61. How to generate the series :
    x+x^2/3-x^3/4+x^4/5-x^5/6+x^6/7-x^7/8+x^8/9-............. n terms

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  62. How to generate the series :
    x+x^2/3-x^3/4+x^4/5-x^5/6+x^6/7-x^7/8+x^8/9-............. n terms

    ReplyDelete
  63. How to generate the series :
    x+x^2/3-x^3/4+x^4/5-x^5/6+x^6/7-x^7/8+x^8/9-............. n terms

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  64. can you pls give me program for the sequence for 20 , 60 , 104 , 152 , 204 , .......

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  65. please code this series
    1, 9, 17, 33, 49, 73, 97

    ReplyDelete
  66. This comment has been removed by the author.

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  67. i need the same code for this series 1,9,17,33,49,73,97

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  69. A complete website:

    https://www.cprogrammingplus.com/

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  70. can you plz help me to solve the series 1 4 27 256 ....

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  71. Write a program on c++ compute the sum, 𝑆=1+2+4+7+11+⋯+56

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  72. For Complete explanation of C++ please visit - SchoolingAxis

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  73. Generate Following series up to given steps :- 0,1,1,2,3,5,8,13,21,34,.....

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  74. Generate following series
    for N=3 series:- 1 2 1 3 2 1
    for N=5 Series:- 1 2 1 3 2 1 4 3 2 1 5 4 3 2 1

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